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Engineering Aptitude
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Engineering Aptitude quiz-2
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Question 1 of 10
1. Question
1 pointsWhat is the unit digit in(795 – 358)? Correct
Unit digit in 795 = Unit digit in [(74)23 x 73]
= Unit digit in [(Unit digit in(2401))23 x (343)]
= Unit digit in (123 x 343)
= Unit digit in (343)
= 3Unit digit in 358 = Unit digit in [(34)14 x 32]
= Unit digit in [Unit digit in (81)14 x 32]
= Unit digit in [(1)14 x 32]
= Unit digit in (1 x 9)
= Unit digit in (9)
= 9Unit digit in (795 – 358) = Unit digit in (343 – 9) = Unit digit in (334) = 4.
So, Option B is the answer.
Incorrect
Unit digit in 795 = Unit digit in [(74)23 x 73]
= Unit digit in [(Unit digit in(2401))23 x (343)]
= Unit digit in (123 x 343)
= Unit digit in (343)
= 3Unit digit in 358 = Unit digit in [(34)14 x 32]
= Unit digit in [Unit digit in (81)14 x 32]
= Unit digit in [(1)14 x 32]
= Unit digit in (1 x 9)
= Unit digit in (9)
= 9Unit digit in (795 – 358) = Unit digit in (343 – 9) = Unit digit in (334) = 4.
So, Option B is the answer.
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Question 2 of 10
2. Question
1 points(xn – an) is completely divisible by (x – a), when Correct
For every natural number n, (xn – an) is completely divisible by (x – a).
Incorrect
For every natural number n, (xn – an) is completely divisible by (x – a).
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Question 3 of 10
3. Question
1 pointsWhat will be remainder when 17200 is divided by 18 ? Correct
When n is even. (xn – an) is completely divisibly by (x + a)
(17200 – 1200) is completely divisible by (17 + 1), i.e., 18.
(17200 – 1) is completely divisible by 18. On dividing 17200 by 18, we get 1 as remainder.Incorrect
When n is even. (xn – an) is completely divisibly by (x + a)
(17200 – 1200) is completely divisible by (17 + 1), i.e., 18.
(17200 – 1) is completely divisible by 18. On dividing 17200 by 18, we get 1 as remainder. -
Question 4 of 10
4. Question
1 points(12 + 22 + 32 + … + 102) = ?
Correct
We know that (12 + 22 + 32 + … + n2) = 1 n(n + 1)(2n + 1) 6 Putting n = 10, required sum = 
1 x 10 x 11 x 21 
= 385 6 Incorrect
We know that (12 + 22 + 32 + … + n2) = 1 n(n + 1)(2n + 1) 6 Putting n = 10, required sum = 1 x 10 x 11 x 21 = 385 6 -
Question 5 of 10
5. Question
1 pointsWhen a number is divided by 13, the remainder is 11. When the same number is divided by 17, then remainder is 9. What is the number ? Correct
x = 13p + 11 and x = 17q + 9
13p + 11 = 17q + 9 17q – 13p = 2 q =2 + 13p 17 The least value of p for which q = 2 + 13p is a whole number is p = 26 17 x = (13 x 26 + 11)= (338 + 11)
= 349
Incorrect
x = 13p + 11 and x = 17q + 9
13p + 11 = 17q + 9 17q – 13p = 2 q =2 + 13p 17 The least value of p for which q = 2 + 13p is a whole number is p = 26 17 x = (13 x 26 + 11)= (338 + 11)
= 349
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Question 6 of 10
6. Question
1 pointsA, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. After what time will they again at the starting point ?
Correct
L.C.M. of 252, 308 and 198 = 2772.
So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Incorrect
L.C.M. of 252, 308 and 198 = 2772.
So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
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Question 7 of 10
7. Question
1 pointsFind the number of zeros in 75!
Correct
Incorrect
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Question 8 of 10
8. Question
1 pointsWhat is the number of trailing zeroes in 1123!?
Correct
[1123/5] = 224
[224/5] = 44
[44/5] = 8
[8/5]=1. It is less than 5, so we stop here.
The answer is = 224 + 44 + 8 + 1 =277
Incorrect
[1123/5] = 224
[224/5] = 44
[44/5] = 8
[8/5]=1. It is less than 5, so we stop here.
The answer is = 224 + 44 + 8 + 1 =277
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Question 9 of 10
9. Question
1 pointsWhich of the following shows the prime factorization of 84?
Correct
Explanation
Step 1:
We can breakdown 84 into its factors as shown below.
84 = 2 × 42;
42 = 2 × 21;
21 = 3 × 7;
Step 2:
So the prime factorization of 84 is
= 2 × 2 × 3 × 7 = 22 × 3 × 7
Incorrect
Explanation
Step 1:
We can breakdown 84 into its factors as shown below.
84 = 2 × 42;
42 = 2 × 21;
21 = 3 × 7;
Step 2:
So the prime factorization of 84 is
= 2 × 2 × 3 × 7 = 22 × 3 × 7
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Question 10 of 10
10. Question
1 pointsSix bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?
Correct
L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
So, the bells will toll together after every 120 seconds(2 minutes).
In 30 minutes, they will toll together 30 + 1 = 16 times. 2 Incorrect
L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
So, the bells will toll together after every 120 seconds(2 minutes).
In 30 minutes, they will toll together 30 + 1 = 16 times. 2