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Engineering Aptitude
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time speed and distance Quiz-4
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Question 1 of 10
1. Question
1 pointsA person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
Correct
Speed = 
600 
m/sec.5 x 60 = 2 m/sec.
= 2 x 18 km/hr 5 = 7.2 km/hr.
Incorrect
Speed = 600 m/sec.5 x 60 = 2 m/sec.
= 2 x 18 km/hr 5 = 7.2 km/hr.
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Question 2 of 10
2. Question
1 pointsA man goes to Mumbai from Pune at a speed of 4 km/hr and returns to Pune at speed of 6km/hr. What is his average speed of the entire journey?
Correct
Incorrect
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Question 3 of 10
3. Question
1 pointsIf a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Correct
Let the actual distance travelled be x km.
Then, x = x + 20 10 14 
14x = 10x + 200 4x = 200 x = 50 km.Incorrect
Let the actual distance travelled be x km.
Then, x = x + 20 10 14 14x = 10x + 200 4x = 200 x = 50 km. -
Question 4 of 10
4. Question
1 pointsExcluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Correct
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9 x 60 min= 10 min. 54 Incorrect
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9 x 60 min= 10 min. 54 -
Question 5 of 10
5. Question
1 pointsIn a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Correct
Let the duration of the flight be x hours.
Then, 600 – 600 = 200 x x + (1/2) 600 – 1200 = 200 x 2x + 1 x(2x + 1) = 3 2x2 + x – 3 = 0 (2x + 3)(x – 1) = 0 x = 1 hIncorrect
Let the duration of the flight be x hours.
Then, 600 – 600 = 200 x x + (1/2) 600 – 1200 = 200 x 2x + 1 x(2x + 1) = 3 2x2 + x – 3 = 0 (2x + 3)(x – 1) = 0 x = 1 h -
Question 6 of 10
6. Question
1 pointsA man completes a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and the second half at the rate of 24 km/hr. Find the total journey in km.
Correct
1/2)x + (1/2)x = 10 21 24 x + x = 20 21 24 15x = 168 x 20 x =168 x 20 = 224 km. 15 Incorrect
1/2)x + (1/2)x = 10 21 24 x + x = 20 21 24 15x = 168 x 20 x =168 x 20 = 224 km. 15 -
Question 7 of 10
7. Question
1 pointsA farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance travelled on foot is:
Correct
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 –x) km.
So, x + (61 –x) = 9 4 9 9x + 4(61 –x) = 9 x 36 5x = 80 x = 16 km.Incorrect
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 –x) km.
So, x + (61 –x) = 9 4 9 9x + 4(61 –x) = 9 x 36 5x = 80 x = 16 km. -
Question 8 of 10
8. Question
1 pointsA boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
Correct
Speed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = 68 hrs = 4 hrs.17 Incorrect
Speed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = 68 hrs = 4 hrs.17 -
Question 9 of 10
9. Question
1 pointsA boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively? Correct
Let the man’s rate upstream be x kmph and that downstream be y kmph.
Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.
x x 8 4 = (y x 4) 5 44 x =4y 5 y =11 x. 5 
Required ratio =y + x : y – x 2 2 = 16x x 1 : 6x x 1 5 2 5 2 = 8 : 3 5 5 = 8 : 3.
Incorrect
Let the man’s rate upstream be x kmph and that downstream be y kmph.
Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.
x x 8 4 = (y x 4) 5 44 x =4y 5 y =11 x. 5 Required ratio =y + x : y – x 2 2 = 16x x 1 : 6x x 1 5 2 5 2 = 8 : 3 5 5 = 8 : 3.
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Question 10 of 10
10. Question
1 pointsA motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
Correct
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 – x) km/hr.
30 + 30 = 4 1 (15 + x) (15 – x) 2 900 = 9 225 – x2 2 9x2 = 225 x2 = 25 x = 5 km/hr.Incorrect
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 – x) km/hr.
30 + 30 = 4 1 (15 + x) (15 – x) 2 900 = 9 225 – x2 2 9x2 = 225 x2 = 25 x = 5 km/hr.